how to remove new line in bash using echo

packets · 11-24-2009, 07:01 PM

I created a simple bash script. My primary concern is how to remove the new line in the output of my script in /root/test.txt

Synopsis

Quote:

./script.sh foo fee

Content

Quote:

case $1 in
*)
echo -ne "
$1
$2" > /root/test.txt

The output of this is

Quote:

foo
fee

I want to remove the new line above the foo. Is it possible?

ghostdog74 · 11-24-2009, 07:40 PM

use printf instead of echo

Code:

printf "%s\n%s " $1 $2

dxqcanada · 11-24-2009, 07:42 PM

Remove the new line.

Code:

case $1 in
*)
echo -ne "$1
$2" > /root/test.txt

packets · 11-24-2009, 07:47 PM

@dxqcanada

Thanks..Forgot that it creates a new line because of '"'

colucix · 11-24-2009, 07:47 PM

Also note that in your code you explicitly told echo to print out a leading newline:

Code:

echo -ne "\n
$1\n
$2"

the -n option of echo serves to avoid the trailing newline only.

Edit: ooops... too late!

packets · 11-24-2009, 07:56 PM

@colucix

yes.. forgot to remove the "-e"

Thanks!

packets · 11-24-2009, 08:36 PM

forgot to tell this.

Can I make it short that instead of writing

Quote:

case $1 in
*)
echo -ne "
$1
$2 $3 $4 $5 $6 $7 $8 $9" > /root/test.txt

Is there a way I can shortened the portion $2 $3 $4 $5 $6 $7 $8 $9 up to variable I want let's say $100.

I though $[2-100] is ok but instead it do an arithmetic which was $98.

dxqcanada · 11-24-2009, 08:48 PM

You should read up on using loops ... and shift.

packets · 11-24-2009, 08:56 PM

@dxqcanada

Can I use loop inside the echo?

dxqcanada · 11-24-2009, 09:00 PM

No.

Kind of like this:

Start the loop as long as there are parameters

echo the parameter ... append to file

shift the parameter to the next

go to beginning of loop