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Old 04-17-2013, 07:04 AM   #1
say_hi_ravi
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How to find a specific word between two lines having same another word..


Hi,

First of all apologies for that poor statement I wrote - my bad english :-(

Let me elaborate in example what I exactly need.

I have a java app log file containing different exceptions.

Code:
$ vi java.log

2013-01-23 21:19:32,621 INFO [STDOUT] (my-nio-server-WorkerThread-4029) [LCDS]01/23/2013 GatewayEndpoint 'gateway-endpoint' failed to process a synchronized authentication.
flex.messaging.security.SecurityException: External login command required. Please check your security configuration.
at flex.messaging.security.LoginManager.login(LoginManager.java:245)
at flex.messaging.endpoints.GatewayEndpoint$GatewayEndpointProtocolHandler.processAuthenticationSyncOperation(GatewayEndpoint.java:874)
at flex.messaging.endpoints.GatewayEndpoint$GatewayEndpointProtocolHandler.processReceivedGatewayMessage(GatewayEndpoint.java:836)
at flex.messaging.endpoints.GatewayEndpoint$GatewayEndpointProtocolHandler.processReceivedMessage(GatewayEndpoint.java.exception:779)
at flex.messaging.endpoints.AMFSocketProtocolHandler.processReceivedMessageChunk(AMFSocketProtocolHandler.java:158)
at flex.messaging.io.amfsocket.AMFSocketInput.read(AMFSocketInput.java:139)
at flex.messaging.endpoints.AMFSocketProtocolHandler.doRead(AMFSocketProtocolHandler.java:132)
2013-01-23 22:30:44,044 INFO [org.apache.axis2.transport.http.HTTPSender] (http-0.0.0.0-8080-9) Unable to sendViaPost to url[https://www.zuora.com/apps/services/a/43.0]
org.apache.commons.httpclient.ConnectionPoolTimeoutException: Timeout waiting for connection
at org.apache.commons.httpclient.MultiThreadedHttpConnectionManager.doGetConnection(MultiThreadedHttpConnectionManager.java:497)
at org.apache.commons.httpclient.MultiThreadedHttpConnectionManager.getConnectionWithTimeout(MultiThreadedHttpConnectionManager.java:416)
at org.apache.commons.httpclient.HttpMethodDirector.executeMethod(HttpMethodDirector.java:153)
at org.apache.commons.httpclient.HttpClient.execute(HttpClient.java.exception:397)
at org.apache.axis2.transport.http.AbstractHTTPSender.executeMethod(AbstractHTTPSender.java:621)
at org.apache.axis2.transport.http.HTTPSender.sendViaPost(HTTPSender.java:193)
2013-01-23 22:30:44,044 INFO [org.apache.axis2.transport.http.HTTPSender] (http-0.0.0.0-8080-9) Unable to sendViaPost to url[https://www.zuora.com/apps/services/a/43.0]
org.apache.commons.httpclient.ConnectionPoolTimeoutException: Timeout waiting for connection
at org.apache.commons.httpclient.MultiThreadedHttpConnectionManager.doGetConnection(MultiThreadedHttpConnectionManager.java:497)
at org.apache.commons.httpclient.MultiThreadedHttpConnectionManager.getConnectionWithTimeout.exception(MultiThreadedHttpConnectionManager.java:416)
at org.apache.commons.httpclient.HttpMethodDirector.executeMethod(HttpMethodDirector.java:153)
I want to find how many "exception" words are there between line having "INFO" word in them.

ie. for example, in below section there are two exception errors..

Code:
2013-01-23 21:19:32,621 INFO [STDOUT] (my-nio-server-WorkerThread-4029) [LCDS]01/23/2013 GatewayEndpoint 'gateway-endpoint' failed to process a synchronized authentication.
flex.messaging.security.SecurityException: External login command required. Please check your security configuration.
at flex.messaging.security.LoginManager.login(LoginManager.java:245)
at flex.messaging.endpoints.GatewayEndpoint$GatewayEndpointProtocolHandler.processAuthenticationSyncOperation(GatewayEndpoint.java:874)
Unable to sendViaPost to url[https://www.zuora.com/apps/services/a/43.0]
org.apache.commons.httpclient.ConnectionPoolTimeoutException: Timeout waiting for connection
2013-01-23 22:30:44,044 INFO [org.apache.axis2.transport.http.HTTPSender] (http-0.0.0.0-8080-9) Unable to sendViaPost to url
Thanks in advance.

Regards,
Ravi
 
Old 04-17-2013, 07:15 AM   #2
danielbmartin
Senior Member
 
Registered: Apr 2010
Location: Apex, NC, USA
Distribution: Mint 17.3
Posts: 1,881

Rep: Reputation: 660Reputation: 660Reputation: 660Reputation: 660Reputation: 660Reputation: 660
Quote:
Originally Posted by say_hi_ravi View Post
I want to find how many "exception" words are there between line having "INFO" word in them.
Please provide a sample output file which corresponds to the sample input file already posted. That, along with your words, will help us to understand your goal.

Daniel B. Martin
 
Old 04-18-2013, 02:47 PM   #3
David the H.
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Registered: Jun 2004
Location: Osaka, Japan
Distribution: Arch + Xfce
Posts: 6,852

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Perhaps something like this?

Code:
awk '/INFO/ { count[++n]=0 } ; /Exception/ { count[n]++ } ; END{ for (i in count){ printf "section %d has %d exceptions\n",i,count[i] } }' | sort -k1n
 
1 members found this post helpful.
Old 04-18-2013, 06:12 PM   #4
danielbmartin
Senior Member
 
Registered: Apr 2010
Location: Apex, NC, USA
Distribution: Mint 17.3
Posts: 1,881

Rep: Reputation: 660Reputation: 660Reputation: 660Reputation: 660Reputation: 660Reputation: 660
Quote:
Originally Posted by David the H. View Post
Perhaps something like this?

Code:
awk '/INFO/ { count[++n]=0 } ; /Exception/ { count[n]++ } ; END{ for (i in count){ printf "section %d has %d exceptions\n",i,count[i] } }' | sort -k1n
I like this solution, and offer a minor improvement...
Code:
awk '/INFO/ {count[++n]=0}; /Exception/ {count[n]++};
  END{for (i=1;i<=n;i++)
  {printf "section %d has %d exceptions\n",i,count[i]}}' $InFile >$OutFile
...which produces the same result without needing the sort step.

Daniel B. Martin
 
1 members found this post helpful.
Old 04-18-2013, 06:37 PM   #5
David the H.
Bash Guru
 
Registered: Jun 2004
Location: Osaka, Japan
Distribution: Arch + Xfce
Posts: 6,852

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Yeah, I should've thought of that. I hate having to fight with awk's lack of easy array control and tend towards the laziest approach. awk really needs to get a few built-in array and field range functions; splicing and sorting can be so annoying.
 
  


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