LinuxQuestions.org - [SOLVED] How to direct standard output from find command

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How to direct standard output from find command

Hello everyone,

I'm trying to pull out sections from a bunch of files. For one file, I use:

Code:

sed '/string1/,/string2/ !d' <filename.ext >newfilename.ext

to pull out everything between two strings in the original file and put them in a new file. I would like to do this for all files in a directory. I have tried:

Code:

find . -type f -name '*.ext' -exec sed '/string1/,/string2/ !d' {} >./NewDirectory/{}\;

This results in a single output file in NewDirectory named {}. {} contains output from all of the files found by find. I would like each output to be in a separate file with the same name as the original file. What am I doing wrong?

Thank you for your help!

I've found the simplest approach is to put your complex command inside an executable script file, and use pass it the filename as a parameter.

Code:

echo "sed '/string1/,/string2/ !d' <${1} >NewDirectory/${1}" > sedscript.sh

chmod 755 sedscript.sh

find . -type f -name '*.ext' -exec ./sedscript.sh {} \;

It just makes life easier I think.

I don't think that it will work in this way. The problem is that the shell concludes that the command has ended when it sees the redirection operator (>), so the filename here is no longer within the scope of the find command.

Have you tried this instead?:

Code:

for file in `find . -type f`; do

sed '/string1/,/string2/ !d' <$file >./directory/$file

fi

Thank you Ian and Robhogg for your helpful replies. I ended up using a shell script as suggested.