How sort data in some file which are greater than some value?

sarajevo · 08-24-2006, 03:46 AM

Hi people,

I would like to ask you something:
In some .txt folder I have many numbers, and using awk ' { print $2 , $3 ,....} ' I can filter data and write them to some directory. Some columns has data like below
2
3
4
5
6
10
11
12
13
my question is how filter data in this colone but only numbers greater or equal to 10 I mean >=10, ( 10, 11, 12, 13 ) and write them to some folder using redirection. Every hint is welcome.

Thanks in advance

Regards

pwc101 · 08-24-2006, 03:56 AM

you could do it with an if statement in awk:

Code:

 awk '{(if $1>=10) print $1}' input.file > output.file

/bin/bash · 08-24-2006, 04:28 AM

grep [1-9][0-9] file >file2

sarajevo · 08-24-2006, 12:32 PM

Thank you.

Tinkster · 08-24-2006, 01:31 PM

Quote:

Originally Posted by /bin/bash

grep [1-9][0-9] file >file2

Unless of course >10 includes 100 + ;} ...

Cheers,
Tink

/bin/bash · 08-25-2006, 03:48 AM

Quote:

Unless of course >10 includes 100 + ;} ...

What do you mean?

$seq 90 2 110 >file;seq 1 12 >>file
$grep [1-9][0-9] file
90
92
94
96
98
100
102
104
106
108
110
10
11
12