How Get "Unmodified" Command-Line Arguments?

cbh2000 · 09-10-2010, 08:17 PM

Is there a way to retrieve the arguments in one big string, rather than split into a "char*[]" in C/C++?

It would be nice to get this: "appname --option=value argument argument", rather than "appname", "--option=value", "argument", "argument", etc...

Simply concocting the strings together will not do, since I would like to get the arguments before any OS interaction (i.e.,

Code:

appname --option="hello"

translates into

Code:

appname --option=hello

(quotes are lost). Here is the output of just such a problem:

Code:

bryan@linux-qgp0:~> printargs a "b" ""c""
Argument 0 is: "printargs"
Argument 1 is: "a"
Argument 2 is: "b"
Argument 3 is: "c"

As you can see, the quotation marks are lost...

rriggs · 09-10-2010, 08:55 PM

Short answer: no. Long answer: it depends on what shell you use. You can write your own shell that passes the entire command-line as the second arg of execl(). It's not going to work with any other Unix program that requires command-line arguments, so the general utility of that shell will be rather limited.