LinuxQuestions.org - how do i simulate a form post with cookies in it?

I am attempting to mimic a form post or [simulate a form post]
I have a form on my website that sets cookies in the header when the initial form page loads.
I think i a\have the script set up correctly to send the form data.

My problem:

I am trying to figure out how to send the cookie that is set in the header when i
send other form variables via php.

the script that sets the cookies is below:

Code:

 <script type="text/javascript">



function SetCookie(name, value) {

            var today  = new Date();

            var expire = new Date();

            expire.setTime(today.getTime() + (60*60*24*30));

            document.cookie = 'serendipity[' + name + ']='+escape(value) + ';expires=' + expire.toGMTString();

        }

        </script>

now b4 i get beat up 4 putting a javascript code in php section:

my php file [zend02.php] is:

PHP Code:




<?php  
 
  require_once "HTTP/Request.php"; 
 
include("postit2.php"); 
 
$req =& new HTTP_Request("http://www.abc.com/userz/mel/ser_admin.php"); 
 
 
$response = $req->sendRequest(); 
 
if (PEAR::isError($response)) { 
    echo $response->getMessage(); 
} else { 
    print_r($response->getResponseCookies()); 
} 
 
  $data["dbType"] = "mysql"; 
  $data["dbHost"] = "localhost"; 
  $data["dbUser"] = "mem"; 
  $data["dbPass"] = "letmein"; 
  $data["dbName"] = "me"; 
 
 
 
  $result = post_it2($data, " [url]http://www.abc.com/userz/mel/ser_admin.php[/url]");  
 
  if (isset($result["errno"])) {  
    $errno = $result["errno"];  
    $errstr = $result["errstr"];  
    echo "<B>Error $errno</B> $errstr";  
    exit;  
  } else {  
 
    for($i=0;$i< count($result); $i++) echo $result[$i];  
 
  }  
 
?>

the postit2.php file referenced above:

PHP Code:





<?php 
 
function post_it2($data, $URL) { 
 
//  Strip [url]http://[/url] from the URL if present 
    $URL = ereg_replace("^[url]http://[/url]", "", $URL); 
 
//  Separate into Host and URI 
    $Host = substr($URL, 0, strpos($URL, "/")); 
    $URI = strstr($URL, "/"); 
 
//  Form up the request body 
    $ReqBody = ""; 
    while (list($key, $val) = each($data)) { 
      if ($ReqBody) $ReqBody.= "&"; 
      $ReqBody.= $key."=".urlencode($val); 
    } 
    $ContentLength = strlen($ReqBody); 
 
//  Generate the request header 
    $ReqHeader = 
      "POST $URI HTTP/1.0\n". 
      "Host: $Host\n". 
      "User-Agent: PostIt\n". 
      "Content-Type: application/x-www-form-urlencoded\n". 
      "Content-Length: $ContentLength\n\n". 
      "$ReqBody\n"; 
 
//     echo $ReqHeader; 
 
 
//  Open the connection to the host 
    $socket = fsockopen($Host, 80, &$errno, &$errstr); 
    if (!$socket) { 
      $Result["errno"] = $errno; 
      $Result["errstr"] = $errstr; 
      return $Result; 
    } 
    $idx = 0; 
    fputs($socket, $ReqHeader); 
    while (!feof($socket) && $Result[$idx-1] != "0\r\n") { 
    if (substr($Result[$idx-1], 0, 2) == "0\r\n") echo "The End:".strlen($Result[$idx-1]); 
      $Result[$idx++] = fgets($socket, 128); 
    } 
    return $Result; 
  } 
?>

my php code to simulate the form on my website gives the following error when used:

Fatal error: Call to a member function on a non-object in /var/www/html/zend02.php on line 15

now i was told i am recieving the 'non object error' because sendRequest in the 1st code is returning an array.
how can i have the cookie variable sent with the form?