How can i subtract two non-real (aka decimal'd) numbers via bash

onesikgypo · 04-28-2010, 11:15 AM

Hi,

I just need to perform a simple operation of subtracting two numbers - that aren't whole numbers, i.e 200.56 - 67.24

attempting to use expr i merely get "expr: non-numeric argument"

Any assistance would be greatly appreciated.

Thanks

grail · 04-28-2010, 11:21 AM

Code:

echo | awk '{print 200.56 - 67.24}'

or

Code:

echo '200.56 - 67.24' | bc

pixellany · 04-28-2010, 11:45 AM

Semantics police here....
Those are real numbers---they are just not integers. ("real" is typically the opposite of "imaginary"---the latter being some product of sqrt(-1))

My favorite real-time calculator is now Python

Sergei Steshenko · 04-28-2010, 11:55 AM

Quote:

Originally Posted by pixellany

Semantics police here....
Those are real numbers---they are just not integers. ("real" is typically the opposite of "imaginary"---the latter being some product of sqrt(-1))

My favorite real-time calculator is now Python

Code:

perl -e 'print 9.8 - 7.6'
2.2