hex notation to a C compiler

rhoyerboat · 02-16-2005, 06:02 AM

okay, so, hex addresses to a C compiler, i see 0xc6 and 0xc60, although i cant get shake the thought that someone who should have been going 0x0000c6 or 0xc60000 was being lazy..
or it could also be that 0xc6 is 198d and 0xc60 is 3168d, the fact is that i just dont know, can someone point me in the right direction real quick?

frob23 · 02-16-2005, 06:34 AM

I'm confused as to what you are asking.

There is nothing lazy about writing 0x23a instead of 0x00000023a.

Just like there is nothing lazy about writing 123 instead of 0000000000123. Leading zeros are meaningless.

michaelk · 02-16-2005, 06:36 AM

AFAIK 0xc6 = 198d

itsme86 · 02-16-2005, 09:05 AM

Just like in decimal, trailing zeroes in a hex number are multipliers. In hex, each trailing zero happens to multiply the result by 16 decimal. Also, just like in decimal, leading zereos in a hex number mean absolutely nothing.

So yeah, here's what you've got:
0xc6 = 198d
0x0c6 = 198d
0xc60 = 3168d

Does that answer your question?

deiussum · 02-16-2005, 09:12 AM

Just as an aside, in C/C++ 0000000000123 would actually be an octal literal because of the leading 0, so it would be 83 decimal.

So in C/C++, 0123 != 123.

rhoyerboat · 02-16-2005, 09:42 AM

lol, thanks