[SOLVED] Help: Pass an Input to a Program for test

behzad · 04-13-2011, 12:10 AM

Hey guys I started to run a C++ my program in Linux and I don't know how to test my program that works fine with a text file. This is a project for my uni and to explain more clear, My program is a sample database for modify or add and search and it read data from a binary file and also write into a binary file.
I have got an input from my lecture and she said after compiling in Linux I must
write:

1-to compile:

Code:

 g++ (files with cpp)

2-to see the output:

Code:

 ./a.out

3-to test with input:

Code:

./a.out < input.txt >

My problem is in step three.could you please write exactly what I must write in the command part after" step2" to see the output?

Aquarius_Girl · 04-13-2011, 03:18 AM

qq.c

Code:

#include <stdio.h>

int main(int argc,char *argv[]) 
{
     printf ("filename: %s\n", argv[1]);
     return 0;
}

Code:

[13:54:10 Wed Apr 13]
~/notes gcc junk/qq.c
[13:54:28 Wed Apr 13]
~/notes ./a.out const.cpp
filename: const.cpp
[13:54:33 Wed Apr 13]
~/notes

Ramurd · 04-13-2011, 05:53 AM

Code:

#include <stdio.h>
#include <errno.h>

int main(int argc, char *argv)
{
   FILE *fp;
   char ugly_buffer[1024];

   if(argc < 2)
   {
      printf("Usage: %s <file>\n",argv[0]);
      return 1;
   }

   fp=fopen(argv[1],"ro");
   if(!fp)
   {
       ugly_buffer=sprintf(ugly_buffer,"Could not open file %s for reading;\nReason: ",argv[1]);
       perror(ugly_buffer);
       return errno;
   }

   /* do stuff with the file */
   fclose(fp);

   return 0;
}

MTK358 · 04-13-2011, 12:38 PM

Code:

int main(int argc, char *argv)
{
    if (argv < 2) {
        fprintf(stderr, "Not enough arguments.\n");
        return 1;
    } else if (argv > 2) {
        fprintf(stderr, "Too much arguments.\n");
        return 1;
    }

    // do stuff. The filename will be in argv[1].

    return 0;
}