help me find a BUG in a little C++ program
 

This is my source of program

[root@localhost mycpp]# ls
dive.cpp dive.h glibc.c linuxsoc main.cpp try1.cpp try2.cpp
[root@localhost mycpp]# cat try1.cpp
#include <iostream.h>

int main () {
char myarray[10];
try
{
for (int n=0; n<=10; n++)
{
if (n>9) throw "Out of range";
myarray[n]='z';
}
}
catch (char * str)
{
cout << "Exception: " << str << endl;
}
return 0;
}
[root@localhost mycpp]#

so I compile it

[root@localhost mycpp]# make try1
g++ try1.cpp -o try1
In file included from /usr/include/c++/3.2.2/backward/iostream.h:31,
from try1.cpp:1:
/usr/include/c++/3.2.2/backward/backward_warning.h:32:2: warning: #warning This file includes at least one deprecated or antiquated header. Please consider using one of the 32 headers found in section 17.4.1.2 of the C++ standard. Examples include substituting the <X> header for the <X.h> header for C++ includes, or <sstream> instead of the deprecated header <strstream.h>. To disable this warning use -Wno-deprecated.
[root@localhost mycpp]#

and run the program so this is my result ------------->>

[root@localhost mycpp]# ./try1
Aborted
[root@localhost mycpp]#

what's up??
I think the output must be "Exception: Out of range"


:confused:

catch (const char *str)

and <iostream.h>

changes to <iostream> and using namespace std; to get rid of the warnings.

the problem is your throwing "Out of range" which is a const char * which is not castable to a char * hence why its not being caught. you can fix this by either catching const char * or by throwing something castable to a char *

Or even catch (...)

kev's comment reminds me of a nice article about exception handling and casting, which, although not immediately relevent here might be of interest to anyone reading the thread:

http://www.cuj.com/documents/s=7979/...lop/hyslop.htm

HTH