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03-07-2004, 09:35 PM
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#1
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Member
Registered: Nov 2002
Distribution: Slackware 8.1
Posts: 30
Rep:
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Getting PID of running process in C/C++
Hi All,
I would like to obtain the process id of runing processes in the system
The shell equivalent of what I'm trying to do is "ps -ef". If there is sample code I would really appreciate it.
I am using C, and I wish not to use ps or psof
Thanks
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03-07-2004, 09:38 PM
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#2
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Senior Member
Registered: Nov 2000
Location: Seattle, WA USA
Distribution: Ubuntu @ Home, RHEL @ Work
Posts: 3,892
Rep:
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you want getpid. Read man getpid for more info.
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03-07-2004, 09:41 PM
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#3
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Member
Registered: Nov 2002
Distribution: Slackware 8.1
Posts: 30
Original Poster
Rep:
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Hi jtshaw ,
Man getpid, getppid tells me that it is for the current process. However, what I really want is list of running processes not only the current process
thanks
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03-07-2004, 09:51 PM
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#4
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Senior Member
Registered: Nov 2000
Location: Seattle, WA USA
Distribution: Ubuntu @ Home, RHEL @ Work
Posts: 3,892
Rep:
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Ah, sorry bout that.
What I believe the ps function does is reads all the information from /proc. You'll notice a bunch of directories that are numbers. Those numbers are your pids. In each directory you have information about the pids.
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03-07-2004, 09:53 PM
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#5
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Member
Registered: Nov 2002
Distribution: Slackware 8.1
Posts: 30
Original Poster
Rep:
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Heh,
No problem, well that is what I'm trying to do now but it get so troublesome plus we've to look into each of it to find what argument are passed to the process. I wish there's a smart and fast way of doing it.
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03-08-2004, 02:31 AM
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#6
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Member
Registered: Jan 2004
Location: Munich
Distribution: SuSE 9.2, 10.2, 10.3, knoppix
Posts: 276
Rep:
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Why don't you get the source code of ps and study this? I believe it's either
in binutils or shutils, google will tell you where to download it.
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03-08-2004, 03:57 AM
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#7
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Member
Registered: Nov 2003
Location: delhi
Distribution: redhat 8.0 ,fedora
Posts: 32
Rep:
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why don't u use
execv() function
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03-09-2004, 02:31 AM
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#8
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Member
Registered: Nov 2002
Distribution: Slackware 8.1
Posts: 30
Original Poster
Rep:
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Thanks everyone,
I use the method used in ps source. It is a little tedious but it works. execv() is not my option because I'm trying to get the pid of all the process in the system, not only ones started by me.
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03-09-2004, 11:40 AM
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#9
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Senior Member
Registered: Aug 2002
Location: Groningen, The Netherlands
Distribution: Debian
Posts: 2,536
Rep:
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Maybe you can use this?
I posted it here before some time ago.
It scans /proc for all PID's and prints them. Instead of printing the PID you can
put any code to get more info from the /proc/<PID> directory by changing the processdir() function.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <dirent.h>
#include <fnmatch.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <unistd.h>
void processdir(const struct dirent *dir)
{
puts(dir->d_name);
}
int filter(const struct dirent *dir)
{
uid_t user;
struct stat dirinfo;
int len = strlen(dir->d_name) + 7;
char path[len];
strcpy(path, "/proc/");
strcat(path, dir->d_name);
user = getuid();
if (stat(path, &dirinfo) < 0) {
perror("processdir() ==> stat()");
exit(EXIT_FAILURE);
}
return !fnmatch("[1-9]*", dir->d_name, 0) && user == dirinfo.st_uid;
}
int main()
{
/* Based on example in "man scandir" */
struct dirent **namelist;
int n;
n = scandir("/proc", &namelist, filter, 0);
if (n < 0)
perror("Not enough memory.");
else {
while(n--) {
processdir(namelist[n]);
free(namelist[n]);
}
free(namelist);
}
return 0;
}
<edit>
This only prints processes owned by the user running this program. If you prefer all processes, you can reduce filter() to just:
Code:
int filter(const struct dirent *dir)
{
return !fnmatch("[1-9]*", dir->d_name, 0);
}
</edit>
Last edited by Hko; 03-09-2004 at 04:32 PM.
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03-15-2004, 04:33 AM
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#10
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Member
Registered: Nov 2002
Distribution: Slackware 8.1
Posts: 30
Original Poster
Rep:
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Thanks HKO,
your code is cool!
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10-29-2015, 07:05 AM
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#11
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LQ Newbie
Registered: Oct 2015
Posts: 4
Rep:
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Number of all active processes from /proc
program that will create a none zombie child process to display Number of all active processes.can some one help me with this?
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10-29-2015, 07:17 AM
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#12
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Senior Member
Registered: Oct 2011
Location: Budapest
Distribution: Debian/GNU/Linux, AIX
Posts: 4,948
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What is a 'none zombie child process'? What is the definition of 'active process'?
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10-29-2015, 09:39 AM
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#13
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Member
Registered: Nov 2013
Posts: 746
Rep:
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man 5 proc
look at the section about /proc/pid/stat
more precisely the state variable in /proc/pid/stat(us)
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10-29-2015, 01:04 PM
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#14
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Moderator
Registered: Mar 2011
Location: USA
Distribution: MINT Debian, Angstrom, SUSE, Ubuntu, Debian
Posts: 9,914
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Quote:
Originally Posted by ash2006
program that will create a none zombie child process to display Number of all active processes.can some one help me with this?
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When you fork() a child, wait for a termination signal from that child and then the child will not become a zombie. Review the earlier answers regarding how to get your list of all active processes. Note that you've resurrected an 11 year old thread to ask this question, not shown any effort on your part, and should try some programming or scripting efforts first before asking your question.
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10-30-2015, 04:23 PM
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#15
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LQ Newbie
Registered: Oct 2015
Posts: 4
Rep:
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Number of active processes
I have put some effort. And i had this program before posting the question here. But i was not getting the expected output. And i want my question to be short. So i didnt post my program.
#include <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <unistd.h>
void main(){
int pid1,pid2,pid3;
int pfds1[2], pfds2[2];
char foo[4096];
pipe(pfds1); pipe(pfds2);
pid1 = fork();
if(pid1==0)
{
close(1); dup(pfds1[1]);
close(pfds1[0]);close(pfds1[1]);
close(pfds2[0]);close(pfds2[1]);
execlp("/bin/ps","ps","-A",NULL);
}
else
{
pid2 = fork();
if(pid2==0){
close(0); dup(pfds1[0]);
close(1); dup(pfds2[1]);
close(pfds1[0]);close(pfds1[1]);
close(pfds2[0]);close(pfds2[1]);
execlp("/usr/bin/wc","wc","-l",NULL);
}
}
close(pfds1[0]);close(pfds1[1]);
close(pfds2[0]);close(pfds2[1]);
//Parent waits for all of its 3 children to finish execution
wait(NULL);wait(NULL);wait(NULL);
int nbytes = read(pfds1[0], foo, sizeof(foo));
printf("Output: (%.*s)\n", nbytes, foo);
}
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