gcc warning compiling C code
 

What does "warning: `or' of unmatched not-equal tests is always 1" mean?
That is the warning generated by gcc.

In particular, what is "always 1" or "unmatched" about

if ( (!((x>>(BITS*i))&MASK)) || (((x>>(BITS*i))&MASK) == MASK) ) {
if (d) h++;
else nh++;
} else {
if (d) f++;
else nf++;
}

I assume it's because of what BITS or MASK are set to. What's the rest of that function look like? And what are BITS and MASK set to?

Yep, that was it. I naively supposed there was something "unmatched"; that threw me off.

Thanks