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gcc 3.4.2 and template issue

I want to compile the following code segment:

Code:



namespace VE {



template <class T> class tset :public std::set<T>

{



public:



    T* Find(const T& key){

        iterator i = find(key);

        return i == end() ? 0 : &(*i);

    }



    const T* Find(const T& key) const{

        const_iterator i = find(key);

        return i == end() ? 0 : &(*i);

    }

};



}

This was originally developed in VC and now i am trying to port it to gcc.

However gcc produced these error messages:

Code:

tset.h: In member function `const T* VE::tset<S, T>::Find(const S&):

tset.h:39: error: expected `;' before "i"

tset.h:40: error: `i' undeclared (first use this function)

tset.h:40: error: (Each undeclared identifier is reported only once for each function it appears in.)

tset.h: In member function `const T* VE::tset<S, T>::Find(const S&) const':

tset.h:45: error: `const_iterator' undeclared (first use this function)

tset.h:45: error: expected `;' before "i"

tset.h:46: error: `i' undeclared (first use this function)

Any idea on how to solve this problem is appreciated

This code compiles using gcc 3.3.3. It may work for your version too, but you may encounter problems because the gcc 3.4.x series is more standard compliant than gcc 3.3.* is and will balk one some invalid code that earlier versions accepted.

Code:

#include <set>



namespace VE {



template<typename T>

class tset : public std::set<T>

{



public:



  T* Find(const T& key)

  {

      typename tset::iterator i = find(key);

      return i == end() ? 0 : &(*i);

  }



  const T* Find(const T& key) const

  {

      typename tset::const_iterator i = find(key);

      return i == end() ? 0 : &(*i);

  }

};



}



int

main()

{

  VE::tset<int> myset;

  

  return 0;

}

Hope this helps