LinuxQuestions.org - [SOLVED] FUSE filesystem SETATTR function not implemented

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smeezekitty

11-16-2009 02:57 AM

FUSE filesystem SETATTR function not implemented

i wrote a fuse filesystem driver (for my operating system filesystem),
it is reading but when i write i get this message :

Code:

  unique: 402, error: 0 (Success), outsize: 136

unique: 403, opcode: SETATTR (4), nodeid: 9, insize: 128

  unique: 403, error: -38 (Function not implemented), outsize: 16

i have googled around and not found an awnser
here is my fuse structure:

Code:

static struct fuse_operations jfs_oper = {

.getattr = jfs_getattr,

.readdir = jfs_readdir,

.open = jfs_open,

.read = jfs_read,

.write = jfs_write,

.mknod = jfs_create_file,

.unlink = jfs_unlink,

.setxattr = stub,

.truncate = stub,

.chmod = stub,

.chown = stub,

.utime = stub

};

theNbomr

11-17-2009 11:50 PM

The attributes of a filesystem element are set by the filesystem itself. You can only define any attributes of a filesystem element when you open() it. For example, a file can be opened read-only. Once it is open, this status can only be gotten, and not set. The exceptions would be the chown()/chmod() operations, which have their own specific handlers.
Fuse is a very cool thing.
--- rod.

smeezekitty

11-18-2009 12:52 PM

Quote:

Originally Posted by theNbomr (Post 3760866)

found the problem already, the compile did not compile my changes because there was an error. thanks anyway.

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