LinuxQuestions.org - [SOLVED] FTP Help (with BASH)

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FTP Help (with BASH)

Hello again. :)

I've gotten most of my script working; however I am getting the following error:

Code:

Couldnt get a file descriptor referring to the console

I would very much appreciate any assistance in understanding what I am doing wrong, I searched the interwebz to no avail, so now I am appealing to you wonderful, intelligent, helpful people once again. :) Here is the script:

Code:

#!/bin/bash -xvd

host=$1

user=$2

pass=$3

dir=$4



company=$5



quser=$6

qpass=$7

qhost=$8

qdbase=$9



declare -a myarray

let count=0



#Query

myarray=($(mysql -N -u$quser -p$qpass -h$qhost -D$qdbase -e "SELECT id FROM table;"))



#start FTP

for id in ${myarray[@]}

do

        ftp -n 2>&1

        open $host << ENDFTP

        {

                print user $user $pass

                print mkdir $dir

                print cd $dir

                print binary

                print mput /dir/to/${id}/

                print echo "&nbsp;&raquo;&nbsp;<b>${id}</b><br />"

                print quit

        }

ENDFTP

done

exit 0

The query just pulls the ID out, which has folders named after the ID and we're FTPing over the folder. I get that error before it even makes it to the mkdir. It might not even be getting to the here; but I'm not 100% sure.

It looks like it's unable to read the "open" command; which I don't understand seeing as I'm in the "FTP" mode when it sends that message. Any thoughts? Perhaps the configuration of the remote FTP server?

The ftp part doesn't look correct to me, try the following instead:

Code:

#start FTP

for id in ${myarray[@]}

do

  /usr/bin/ftp -in $host 2>&1 <<ENDFTP

      user $user $pass

      mkdir $dir

      cd $dir

      binary

      mput /dir/to/${id}/

      echo "&nbsp;&raquo;&nbsp;<b>${id}</b><br />"

      bye

ENDFTP

done

No need for the curly braces. I removed the print parts as well, don't think they are needed.

I actually fixed my issue. For anyone who needs help like this in the future, here's the sample code:

Code:

#!/bin/bash/ -xvd

# ^ This sets the xtrace, verbose, and debug on.



#The following pulls in the variable sent along with the command

host=$1

user=$2

pass=$3

dir=$4



company=$5

adimgs=$6



#sample variables for MySQL query

quser='anonymous'

qpass='pass123'

qhost='myhost'

qdbase='database1'



#Declare array and set count to 0

declare -a myarray

let count=0



#remove any previously created file with this name,

#to prevent appending data prior to new ftp script generation.

rm tmp_$company.txt



#Query, to pull in product ids into array.

#Product IDs are then used to identify folders and image files.

myarray=($(mysql -N -u$quser -p$qpass -h$qhost -D$qdbase -e "SELECT id FROM table;"))



#Start FTP; generating the FTP commands, and sending the output to a text file,

#which will contain all the files to be sent via FTP.

echo "open $host" >> tmp_$company.txt

echo "user $user $pass" >> tmp_$company.txt

echo "mkdir $dir" >> tmp_$company.txt

echo "cd $dir" >> tmp_$company.txt

echo "lcd /products/" >> tmp_$company.txt



#for loop used to loop through the array, identify all the files 

#to be sent via ftp, and generate the ftp commands

for id in ${myarray[@]}

do

        echo "Mirror -R /products/${id}" >> tmp_$company.txt

        #if statement, a flag used to determine whether to send the

        #product advertisement images to the company. If yes, the images are sent.

        if [ $adimgs=="yes" ]; then

                echo "cd /dir/to/${id}/" >> tmp_$company.txt

                echo "mput /product_ads/${id}*.jpg" >> tmp_$company.txt

                echo "cd $dir" >> tmp_$company.txt

        fi

done



lftp -f tmp_$company.txt



exit