LinuxQuestions.org - [SOLVED] Filter a word : Shell Scripting

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raj k yadav

02-18-2014 04:14 AM

Filter a word : Shell Scripting

[root@daassna01vapp02 ~]# grep minlen /etc/pam.d/system-auth
password requisite pam_cracklib.so try_first_pass retry=3 minlen=8 difignore=8 lcredit=-1 ucredit=-1 dcredit=-1 ocredit=-1
[root@daassna01vapp02 ~]#

How can I filter the word "minlen" and separate the number from "minlen=8" so that if condition can be applied to check the number given with "minlen=?".

chrism01

02-18-2014 04:25 AM

quick n dirty soln

Code:

grep minlen /etc/pam.d/system-auth |cut -d'=' -f3|cut -d' ' -f1

8

raj k yadav

02-18-2014 06:04 AM

Thanks for replying chrism01, but I need to run the script for all my servers and its not necessary, everywhere the value is in the same field .

colucix

02-18-2014 07:11 AM

Independently from the position:

Code:

grep minlen /etc/pam.d/system-auth | awk -F= '/minlen/{print $NF}' RS=' '

Use command substitution to retrieve the number and check its value, e.g.

Code:

if [[ $(grep minlen /etc/pam.d/system-auth | awk -F= '/minlen/{print $NF}' RS=' ') -eq 8 ]]

then

  echo minlen is 8

else

  echo minlen is another number

fi

grail

02-18-2014 09:11 AM

tut tut tut ... I would not think I would see the day when colucix would combine a needless command ... lol

Code:

awk -F= '/minlen/{print $NF}' RS=' ' /etc/pam.d/system-auth

I would also generally recommend using (()) when performing arithmetic in bash (personal preference)

raj k yadav

02-23-2014 12:38 PM

Thanks for your replies Colucix and Grail. Your solutions worked :)

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