Programming This forum is for all programming questions.
The question does not have to be directly related to Linux and any language is fair game. |
Notices |
Welcome to LinuxQuestions.org, a friendly and active Linux Community.
You are currently viewing LQ as a guest. By joining our community you will have the ability to post topics, receive our newsletter, use the advanced search, subscribe to threads and access many other special features. Registration is quick, simple and absolutely free. Join our community today!
Note that registered members see fewer ads, and ContentLink is completely disabled once you log in.
Are you new to LinuxQuestions.org? Visit the following links:
Site Howto |
Site FAQ |
Sitemap |
Register Now
If you have any problems with the registration process or your account login, please contact us. If you need to reset your password, click here.
Having a problem logging in? Please visit this page to clear all LQ-related cookies.
Get a virtual cloud desktop with the Linux distro that you want in less than five minutes with Shells! With over 10 pre-installed distros to choose from, the worry-free installation life is here! Whether you are a digital nomad or just looking for flexibility, Shells can put your Linux machine on the device that you want to use.
Exclusive for LQ members, get up to 45% off per month. Click here for more info.
|
 |
09-30-2005, 10:36 AM
|
#1
|
LQ Newbie
Registered: Oct 2004
Location: UK
Distribution: Fedora
Posts: 23
Rep:
|
filenames with spaces
I am trying to process a directory and determine attributes of each file. I am using a for x in $( ls ) loop to iterate through the directory, but files with spaces in the name populate ${x} for each word. E.G.
A simple script to list directories
for i in $( ls );
do
if [ -d "${i}" ]; then
echo ${i};
fi;
done
If I have a subdirectory called "This is a file" (without the quotes)
It will look for files: -
This
Is
A
File
which do not exist.
Anyone have any ideas how best to list the directory and just get the filenames individually?
Many Thanks.
|
|
|
09-30-2005, 11:11 AM
|
#2
|
Member
Registered: Aug 2003
Location: Santa Clara, CA
Distribution: Slackware
Posts: 895
Rep:
|
Change the IFS variable like so. (For more info on this variable, try man bash and search for IFS)
Code:
IFS='
'
for i in $( ls -1 );
do
if [ -d "${i}" ]; then
echo ${i};
fi;
done
|
|
|
09-30-2005, 11:11 AM
|
#3
|
Senior Member
Registered: Nov 2004
Location: Texas
Distribution: RHEL, Scientific Linux, Debian, Fedora
Posts: 3,935
Rep: 
|
Try
Code:
ls | awk '{ print }'
And find the person who is creating filenames with spaces in them - make him sit in the corner for awhile.
|
|
|
09-30-2005, 09:04 PM
|
#4
|
Member
Registered: Aug 2004
Location: a small village faraway in the mountains
Distribution: Fedora Core 1, Slackware 10.0 | 2.4.26 | custom 2.6.14.2, Slackware 10.2 | 11.0, Slackware64-13
Posts: 345
Rep:
|
Check this out :
Code:
#!/bin/sh
for i in *;
do
if [ -d "$i" ]; then
echo "$i";
fi;
done
Hope this helps !
PS : Don't forget to put quotes around $i
|
|
|
10-01-2005, 06:39 AM
|
#5
|
Senior Member
Registered: Mar 2004
Location: england
Distribution: Mint, Armbian, NetBSD, Puppy, Raspbian
Posts: 3,516
|
koodoo wins
or:
Code:
ls | while read file;do
echo $file
done
|
|
|
11-01-2005, 04:49 AM
|
#6
|
Member
Registered: Nov 2005
Posts: 90
Rep:
|
I use the following
oldIfs=$IFS
IFS='
'
l=$(find $srcFolder -iname '*.jpg')
for jpgitem in $l; do
IFS=$oldIfs
# do what to do
# cp -v "$jpgitem" "$targetFolder
IFS='
'
done
RGummi
Last edited by RGummi; 11-01-2005 at 01:44 PM.
|
|
|
All times are GMT -5. The time now is 07:53 AM.
|
LinuxQuestions.org is looking for people interested in writing
Editorials, Articles, Reviews, and more. If you'd like to contribute
content, let us know.
|
Latest Threads
LQ News
|
|