file watcher job
 

I need a way to watch for a file and if the file exists run a script.

I think I have most of the pieces.
I am hoping to use cron to run a statement similar to this.

test -e $file
if test -e $file = 0
then execute script
fi

this doesn't seem to work though.
Can anybody tell me what I am doing wrong?


Thanks

I found an answer.

if [ -e $file ] ; then
execute script
fi

This is the proper syntax and seems to work great.