[SOLVED] extract part of string

himu3118 · 05-07-2010, 06:50 AM

i have string like abc0912981-92191.c

i want to extract part between - and . i.e. 92191. the number after abc 0912981 can vary..

Any ideas much appreciated..

druuna · 05-07-2010, 06:58 AM

Hi,

echo $string | sed 's/.*-$.*$.c/\1/'

Hope this helps.

himu3118 · 05-07-2010, 07:03 AM

thanks for the help. its working.

can you please suggest me some links from which i could learn about regular expressions..

druuna · 05-07-2010, 07:10 AM

Hi,

regular expressions aren't the important part in this example (only .* is used). Back referencing is the important part.

All between $ and $ in the search part can be represented as \1 in the replace part.

GNU Sed manual
Sed manual
Sed faq 3

Hope this is what you are looking for.

himu3118 · 05-07-2010, 07:13 AM

thanx agian..

i'll definitely go through these links..