LinuxQuestions.org - [SOLVED] extract lines using date range

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extract lines using date range

I wish to extract lines from files based on date from first two fields eg: lines with todays date or week ago etc
eg of file:
Jul 17 gfgf gfdg sdfg Jul 11
Jul 17 sdfd dfg Jul 11 fdf
Jul 17 ffgg ggg Jul 16 gfg
Jul 16 gfg ffg fdg Jul 17

I used awk suppose for todays date:
k=`date '+%B %d'`
awk -v m="$k" '($1,$2) == m' file

For a week before:
k=`date --date=="7 days ago" +%b\ %e`
awk -v m="$k" '($1,$2) == m' file

For user to enter date for search
echo "enter month"
read mon
echo "enter date"
read dat
awk -v "m=$mon" "d=$dat" '$1 == m && $2 == d' file

where am i going wrong in above scripts
Also if there is other way i could do this

# For Jul 19 - Find lines that have the string "Jul 19" in file.txt

Code:

grep "`date '+%b %d'`" file.txt

# For Jul 19 - Find lines that have the string "Jul 12" 7 days ago in file.txt

Code:

grep "`date '+%b %d' --date='7 days ago'`" file.txt

# For Jul 19 - Find lines that have either string "Jul 12" 7 days ago or the string "Jul 19" in file.txt

Code:

grep -E -e "`date '+%b %d'`|`date '+%b %d' --date='7 days ago'`" file.txt

# For first two columns today

Code:

awk -v date="$(date +"%b %d")" '{if ($1" "$2==date) {print $0}}' file.txt

# For first two columns last week

Code:

awk -v date="$(date +"%b %d" --date="7 days ago")" '{if ($1" "$2==date) {print $0}}' file.txt

# For first two columns last week or today

Code:

awk -v date="$(date +"%b %d" --date="7 days ago")" -v date2="$(date +"%b %d")" '{if ($1" "$2==date || $1" "$2==date2) {print $0}}' file.txt

If this helps please add a rep on the left.

Thanks

thanks sydney was stuck for about two days