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Explain the output(pointers)

explain me the output please .As far as my knowledge. a is a character type pointer variable and its size should be 4 bytes irrespective of what its pointing to.but i get a result =50.
*a is the value of a[0] and its size is rightly 1 byte.
but how can the size of that variable change to 4 byte when i just add 7 to it(although i don't store the added result anywhere)

Code:

#include<stdio.h>

int main(){

        char a[50];

        printf("\n%d  ",sizeof(a));

        printf("\n%d  ",sizeof(*a));

        printf("\n%d  ",sizeof(*a+7));

        return 0;

        }

output:

Code:

Quote:

Originally Posted by ishandutta2007 (Post 3843462)

but i get a result =50.

"a" is an array of 50 chars, so size is correct.
Try this:

Code:

#include<stdio.h>

int main(){

        char a[50];

        char* b = a;

        printf("\n%d  ",sizeof(a));

        printf("\n%d  ",sizeof(b));

        return 0;

}

*a+7 means (*a)+7. And char+int=int.