[SOLVED] expect script for telnet not working

snjksh · 07-27-2013, 10:16 AM

Hi,

Please refer the expect script.

Code:

#!/usr/bin/expect
set timeout 20
set ip [lindex $argv 0]
set port [lindex $argv 1]
set user [lindex $argv 2]
set password [lindex $argv 3]
spawn telnet $ip $port
expect "'^]'." sleep .1;
send "\r";
sleep .1;
expect   "login:"
send "$user\r"
expect "Password:"
send "$password\r";
interact

Getting error while running below command

Code:

#./telnet.sh 192.168.1.10 23 bob redhat

spawn telnet 192.168.1.10 23
Trying 192.168.1.10...
Connected to 192.168.1.10.
Escape character is '^]'.
must have one arg: seconds
while executing
"sleep"
invoked from within
"expect "'^]'." sleep .1"
(file "./telnet.sh" line 8)

TB0ne · 07-27-2013, 10:30 AM

Quote:

Originally Posted by suma5550

Hi,
Please refer the expect script.

Code:

#!/usr/bin/expect
set timeout 20
set ip [lindex $argv 0]
set port [lindex $argv 1]
set user [lindex $argv 2]
set password [lindex $argv 3]
spawn telnet $ip $port
expect "'^]'." sleep .1;
send "\r";
sleep .1;
expect   "login:"
send "$user\r"
expect "Password:"
send "$password\r";
interact

Getting error while running below command

Code:

#./telnet.sh 192.168.1.10 23 bob redhat

spawn telnet 192.168.1.10 23
Trying 192.168.1.10...
Connected to 192.168.1.10.
Escape character is '^]'.
must have one arg: seconds
while executing
"sleep"
invoked from within
"expect "'^]'." sleep .1"
(file "./telnet.sh" line 8)

So did you read the error, and look at line 8??

It very clearly says that the problem is with the sleep command, and that is because sleep takes an argument in seconds. You have not provided it, rather you're trying to pass it ".1" So, pass it a valid argument.