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else: endif not found in csh

I'm getting a 'else: endif not found' error when running the below script to check the number of files in 2 folders is the same. The syntax looks right to me but the output I get is:

Code:

Checking no of files in source and destination.

      2 /

      0 /mnt/Backup/

Items in root locally:

0



Items on dest:

0

All files copied

else: endif not found

Code:

#!/bin/csh



set noFilesLocal = 0

set noFilesRemote = 0



echo 'Checking no of files in source and destination.'



set noFilesLocal = ls | wc -l /

set set noFilesRemote = ls | wc -l /mnt/Backup/



if($noFilesLocal == $noFilesRemote) then

        echo 'Items in root locally:'

        echo $noFilesLocal

        echo ''

        echo 'Items on dest:'

        echo $noFilesRemote

        

        echo 'All files copied'

else

        echo 'Items in root locally:'

        echo $noFilesLocal

        echo ''

        echo 'Items on dest:'

        echo $noFilesRemote

        

        echo 'Not all files copied'

endif

This looks wrong:

Quote:

set set noFilesRemote = ls | wc -l /mnt/Backup/

Also there should be a space before left paren

Quote:

if (

Thanks, I don't know how I didn't spot the two sets. I've also got a working csh script with no space before the parenthesis.

I've changed the start of the file before the if because, as you can see from the output in the first post, the noFilesLocal and noFilesRemote variables are always going to be different as they include file paths. I've been trying to split them on the space character and use that to compare them but I'm having some difficulty with the syntax.

Code:

#!/bin/csh



echo 'Checking no of files in source and destination.'



set noFilesLocal = `ls | wc -l /`

echo $noFilesLocal

set noFilesRemote = `ls | wc -l /mnt/Backup/`

echo $noFilesRemote



set localArr = awk split($noFilesLocal,localArr, ' ')

echo $localArr

set noFilesLocal = $localArr[1]



echo $noFilesLocal

Which gives:

Quote:

Checking no of files in source and destination.
2 /
0 /mnt/Backup/
set: Syntax error

Update:
I found that cd'ing to the directory first instead of passing in the directory gives the number of items only without the file path being appended:

Code:

cd /

set noFilesLocal = `ls | wc -l`

echo $noFilesLocal



cd /mnt/Backup/

set noFilesRemote = `ls | wc -l`

echo $noFilesRemote

that awk will not work also:

Code:

set var = `echo $noFilesLocal | awk ' split ($0, ..... '` # use " " inside awk, not ' '

but in general you cannot manipulate shell variables within awk. It is another language.