Doubt in arrays

psandeepnair1985 · 09-27-2007, 08:03 AM

Hi friends,

I have a major doubt in array concept.
For eg i declare
int a[10];
int b[10][10];

I am confused how &a and a are equal (&a = a)
and
how &b=b=*b..................

I would be thankful to any one who could explain me the logic behind this....

Please help friends.......

pixellany · 09-27-2007, 08:28 AM

First, what language? (looks like C)

Quote:

I am confused how &a and a are equal (&a = a)

They are not equal!!.....I don't understand this question. "&a" means the address of the variable named "a". In the case of an array, the name is the address of the first element. You get the value with either a[n] or *a[..]

bigearsbilly · 09-27-2007, 08:46 AM

array[10][10] is equivalent to array[100]
there is no real 3D in an array of memory obviously,
it's just syntax.

like:

Code:

#include <stdio.h>



main()
{
    char a[10];
    char b[10][10];

    printf("sizeof a = %d\n", sizeof a);
    printf("sizeof b = %d\n", sizeof b);
}

Code:

billym.primadtpdev>make 1 && ./1
gcc     1.c   -o 1
sizeof a = 10
sizeof b = 100