create shell script in makefile

xface66 · 05-07-2007, 02:04 PM

hello everyone;
say i have java source files,
i must write a makefile that compiles the source files and creates an executable shell script

my shell script will be like this;

Code:

#! /bin/bash
$@
	make clean
	make all
	java Server $@
exit 0

when "make all" is typed this must generate the shell script file named "server"

how can i do this?

BrianK · 05-07-2007, 07:22 PM

This sounds an awful lot like homework. For fear that it is, here's some easy pointers:

a target gets defined by a word starting on column 1 & ending with a ':'
a line that starts with a <tab> will be run as a command - like it were run from the command line.

so, a makefile that looks like so:

Code:

foo:
	ls

bar:
	ls -l

will behave like so:

"make foo" will run "ls"
"make bar" will run "ls -l"

there can be more than one command per target - each needs it's own line. Thos commands can be anything - "ls", "g++ foo.C", "java bar", "rm *" - doesn't matter.

All those variables are nice & help you speed things up in the future, but they aren't necessary for now, so save that stuff for later.

btw - there's *loads* more to makefiles than this - this is just a start.

edit: after re-reading your post, the next to last line confuses me. "Server" should be a compiled java binary, right? In other words, your makefile should compile some java for you to a file called "Server" and then this shell script will execute that file - correct?

bigearsbilly · 05-08-2007, 04:26 AM

or use suffixes and default rules:

Code:

.SUFFIXES: .java .class
COMPILE.java = /opt/j2sdk1.4.0_03/bin/javac
CLASSPATH = /opt/app/ipedo/ipedo3.2/lib/xmlclient.jar



.java.class:
 $(COMPILE.java) -classpath ${CLASSPATH}  $<