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Can someone help me awk this line out of a file -

buried within this meta file i have, is another file name. I need to pull the file name out:

<?xml version="1.0"?>ne]# cat example.meta
<Meta>
<FileModTime>1244613601</FileModTime>
<FileSize>3862203</FileSize>
<FileSource>file:///home/log/boyd/archive/boyd.log_2009-06-10T02:00:01.log</FileSource>
</Meta>

I have a ton of these meta files and if they exist i need to pull out the log file:
"/home/log/boyd/archive/boyd.log_2009-06-10T02:00:01.log"

and then delete that log file from another directory -

I think i can script the rest, i just can't figure out how to just pull the log file name out of the meta file

I'm just not very strong with awk, I assume there's a way to do it -

Thx in advance for any tips -

I just came up with this command, but it seems to work, not sure its the most efficient but it works

cat 000-2009-06-10T02:02:11-0-r_boyd.meta |grep archive |awk -F"/" '{ print $8}'|awk -F"<" '{ print $1}'

Let me know if you see anything wrong with passing multiple awk commands

I put your test into a file named "fil":

Code:

[mherring@mystical play]$ awk -F"/" '{print $8}' fil

boyd.log_2009-06-10T02:00:01.log<

This is printing the filename (+ the "<"), but you said you wanted the whole path.

This works:

Code:

[mherring@mystical play]$ sed -n '/archive/{s/<[^>]*>//g;s/file:\/\///p}' fil

/home/log/boyd/archive/boyd.log_2009-06-10T02:00:01.log

[mherring@mystical play]$

If you are happy to change the delimeters this can be made a little shorter:

sed -n '/archive/{s|.*file://$.*$<.*|\1|p}'