C source file Parse error before 38

exvor · 09-18-2005, 05:16 PM

Code:

#include<stdio.h> 
#include<stdlib.h> 
#define SIZE 100

int prog_enterd(int *,int); 

int main()
{ 
   int memory[SIZE];  //simulated memory  
   int mess;
   int acc = 0; 
   int intructcounter; 
   int operationcode,operand; 
   int instruction; 
   int loop; 
   //print welcome message first 
   printf("\n\n"); 
   
   printf("***Welcome to Simcom!***\n***Please enter your program one 
instruction word at a time**\n***I will type the location number and a 
question mark***\n***You then type the word for that 
location***\n***Type the sentinal -99999 to stop entering your 
program***\n");
   mess = prog_enterd(memory,SIZE); 
   if ( mess == 0) 
         {
           printf("You have run out of lines to enter programs or you are at the
 end of memory\n"); 
           exit (0); 
         }

         
   else 
     { printf("Great Program loading compleated\n"); 
     }
   printf("Program execution begins\n"); 
   
 for (intructcounter =0; intructcounter != 43 && intructcounter 
< 99  intructcounter++)  
      { 
         instruction = memory[intructcounter];
         operationcode = instruction / 100; 
         operand = instruction % 100; 
         
         switch (operationcode)
         {
         case 10:     scanf("%d", &memory[operand]); //read
         break; 
         
         case 20:     acc = memory[operand]; //load
         break; 
         
         case 30:     acc += memory[operand]; //add
         break; 
         
         case 43:     printf("Simcom exectution terminated\n"); //HALT
         break; 
         
         case 11:     printf("%d\n",memory[operand]; //write
         break; 
         
         case 21:     memory[operand] = acc; //store
         break; 
         
         case 31:    acc -= memory[operand]; //subtract 
         break; 
        
         case 32:    acc /= memory[operand]; //devide
         break; 

         case 33:    acc *= memory[operand]; //multiply
         break; 
   
         case 40:   intructcounter = operand; 
         break;
 
         case 41:   if (acc < 0) intructcounter = operand; 
         break; 
         
   	 case 42:   if (acc == 0) intructcounter = operand; 
	 break; 
         
     } 
     
     
}
printf("Program execution compleate\n");

printf("Memory dump information"); 

for (loop = 0; loop <= mess; loop++) 
     printf("%02d   %04d%c",loop,memory[loop],(loop % 4 == 0) ? '/n' : ' '); 

return 0;  


} 

int prog_enterd(int *mem, int size)
{ 
     int count = 0;

    do 
     { 
        
        printf("%02d ? ",count); 
        scanf("%d",&mem[count]); 
        printf("\n"); 
        if (mem[count] == -99999) 
             return count - 1; 
        count++;
     } 
     while (count < size); 
     return 0; 

}

strange issue here it says i have a parse error before line 38 ((its in blue))
but i dont see it do any of you see it?

acid_kewpie · 09-18-2005, 05:24 PM

well on line 38 you are missing a ; between 99 and intructcounter++

exvor · 09-18-2005, 05:27 PM

Woops let me check source to make sure thats not in the real source

bulliver · 09-18-2005, 05:51 PM

Also:

Code:

printf("%02d   %04d%c",loop,memory[loop],(loop % 4 == 0) ? '/n' : ' ');

should be:

Code:

printf("%02d   %04d%c",loop,memory[loop],(loop % 4 == 0) ? '\n' : ' ');

With acid's change and mine, the proggy is compiling for me...

Dark_Helmet · 09-18-2005, 05:55 PM

There's one more, but it's only a warning:

Code:

for (loop = 0; loop <= mess; loop++) 
     printf("%02d   %04d%c",loop,memory[loop],(loop % 4 == 0) ? '/n' : ' ');

That's a multi-character, character constant. I assume you intended '\n'

exvor · 09-19-2005, 02:10 PM

Yea I made both changes and now it compiles ok just doesent work as intended.

for some reason my transfer of control doesnt go where intened and the loop doesent stop looping

tho these are issues that i need to solve thanks everyone