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Old 07-07-2005, 08:18 AM   #1
xushi
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Batch Renaming in bash


Hi all, i'm having trouble with renaming files.. i have about 700 of them i need to rename =/ But in 2 parts..

1) There are about 150 files all in 1 folder named
Yannis & Joulia 001.jpg 002 003 004..........
I want to get rid of the & sign.. So its just
Yannis Julia 001.jpg 002 003 .........


2) There are 4 folders with pics that have random names such as
dscn0001.jpg
dscn0002.jpg

How can i just make a loop to rename the pics as
001.jpg
002.jpg
003.jpg
and so on?
And can i tell it to start from another number than 000 ? So when i move to the second folder, i can start from, say 100.jpg, 101.jpg.. etc...

I'm not much of a bash programmer, so i have no idea on how i can do this, although i do know enough that it's probably 1 line of code.. hehe

Thanks alot =)
 
Old 07-07-2005, 08:23 AM   #2
pycoucou
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Hi,

you should try a:

for i in *.jpg
do
mainPart=`echo "$i" | cut -f 1-2 -d '\&'`
mv "$i" "$mainPart"
done

mainPart contains the name of your picture. The cut function allows to do some 'curtting' and you get the field 1 and 2 (-f 1-2) after cutting around the delimiter & (-d '\&').

It should work but maybe the spaces are going to be an issue. Pay attention to that. For the other, you can use the same trick by tuning the cutting part.

PY
 
Old 07-07-2005, 08:34 AM   #3
xushi
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Thanks. I'll give it a try in a short while, and keep the thread updated.
 
Old 07-07-2005, 08:58 AM   #4
xushi
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Hmm, i'm getting this error message
Code:
cut: the delimiter must be a single character
Try `cut --help' for more information.
mv: cannot move `Yannis & Julia 136_jpg.jpg' to `': No such file or directory
Edit: As for the second part, i'm not sure how this would solve it unless i ad some $var += 1; somewhere
 
Old 07-07-2005, 10:08 AM   #5
keefaz
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For the 1) I would do :
Code:
find /path/to/dir -name "*.jpg" | while read file; do 
    new=$(echo $file | tr -d '&')
    [ ! -f "$new" ] && mv "$file" "$new"
done
The 2) would not be too different :
Code:
find /path/to/dir -name "*.jpg" | while read file; do
    new=$(echo $file | sed -e 's/dscn//')
    [ ! -f "$new" ] && mv "$file" "$new"
done
You could use the 2) givin the path to the parent dir
of your 4 jpeg's dir if they are in the same dir

[edit]
If you want 001.jpg become 101.jpg, 002.jpg become 102.jpg...
Code:
find /path/to/dir -name "*.jpg" | while read file; do
    new=$(basename $file)
    dir=$(dirname $file)
    new=$(echo $new | sed -e 's/dscn//')
    new=$(echo $new | cut -d'.' -f1)
    let "new+=100"
    new="$dir/$new.jpg"
    [ ! -f "$new" ] && mv "$file" "$new"
done

Last edited by keefaz; 07-07-2005 at 10:17 AM.
 
Old 07-07-2005, 04:10 PM   #6
pycoucou
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corrections:

mainPart=`echo "$i" | cut -f 1 -d '&'``echo "$i" | cut -f 2 -d '&'`d

Because with the previous syntax:
- & remained
- the delimiter was wrond '&' is sufficient.

Sorry about that
 
Old 07-07-2005, 04:24 PM   #7
xushi
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Thanks. The scripts did the work. And i can move on

They all still look confusing to me, so i don't see myself remembering any of this for a next time :/
 
  


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