BASH: string is "charset=iso-8859-1", I want to extract "iso-8859-1" only. How??
 

Hello all,

I think this is an easy question to answer, but I can't seem to figure it out. 'sed' is for files, not variables...

I get:
as output, the result of
I've stored this little result ("<myfile>: text/x-c++; charset=iso-8859-1") into a variable and would like to get yet another variable which contains the string "iso-8859-1" only (length may vary depending on the encoding), in other words, to extract the part of the string that follows "charset=" up until the end ot the string. It seems simple, but I just can't figure it out!

Thanks in advance,

rm

This should work:
Alternatively, you can use sed:

Alternatively
That is shell parameter expansion. The ## means "strip the longest string matching what comes next from the left side". Shell parameter expansion is a powerful technique and runs faster than using awk, cut or sed (provided the strings are less than a few thousand characters). Unfortunately it's not very intuitive.

Many thanks to both or you. It worked like a charm!

I'm going to post my second question in a separate post (text format conversion, no longer above for those of you who didn't answer this post. It can be found here: http://www.linuxquestions.org/questi...95#post4794795).

rm