bash scripts
 

I wanted to create a script where it will grep the service, output it into a file and kill the services as listed and print it as a log into other file.

How can i capture only the right name services as other might have the same name. For example,

ps -ef | grep vi

root 2138 1 0 09:11:41 ? 0:00 vi something1
root 2709 1072 0 09:13:16 ? 0:01 bvia
root 1511 1466 0 09:10:40 ? 0:04 asbvi

In this case, i just wanted to capture the 'vi' = vi and nothing else...... Can anyone provide a guidance or hints or anything deal with this script?

thanks

try grepping for whole words
HTH

thanks for reply. But in this case, it will still capture the other words contain into it i.e

root 2709 1072 0 09:13:16 ? 0:01 bvia
root 1511 1466 0 09:10:40 ? 0:04 asbvi
root 1511 1466 0 09:10:40 ? 0:04 grep -w vi

The idea is that i want to capture service listing with a spawn child which contain 'vi' and not like ivit, vite or anything.
As you can see, it will output the grep and other stuffs. Any better idea how i can capture exact service name 'vi'?

Any suggestion are fully welcome.

thank you

Sorry. I did not fully get what you are saying.

Is it something like,
you want to find a service which is running and send a kill signal to the process.?

In that case you can use "pidof" to find the pid of the process and kill it