Bash scripting help. Check for file/directory existence

diamond_D · 08-01-2012, 06:56 AM

How can I capture the results of 'ls -l' to store in an array. This way I can create a seperate function to manipulate the array elements as needed.

ntubski · 08-01-2012, 08:37 AM

Quote:

Originally Posted by diamond_D

How can I capture the results of 'ls -l' to store in an array. This way I can create a seperate function to manipulate the array elements as needed.

I think you're on the wrong track, this sounds too complicated. Also, don't parse ls.

Code:

    for file in "${item}"/* ; do
        if [ -f "${file}" ] ; then
            echo "Here is output from ${file}" >> content.txt
            cat "${file}" >> content.txt
        fi
    done

custangro · 08-01-2012, 02:44 PM

Quote:

Originally Posted by diamond_D

How can I capture the results of 'ls -l' to store in an array. This way I can create a seperate function to manipulate the array elements as needed.

To answer your question...

Code:

#!/bin/bash
items=( $(ls -1 /etc ) )
for item in ${items[@]}
do
  file /etc/${item}
done

-C