[SOLVED] Bash Script to Search a Webpage

Nexusfactor · 07-02-2015, 10:39 AM

I've Googled my problem, and it's getting more confusing.

I want to write a bash script that will search this page for a specific string and echo if it's found. For example, if I wanted to search for the string "Game Developer", which exists on the page, it would echo "Found Game Developer!"

I'm not sure where to even begin. I'm using Lubuntu 14.04.2 LTS

This best I came up with is this:

wget -q -O- http://www.centennialcollege.ca/prog.../job-postings/ | grep -c "Game Developer"

Is this the correct way of doing it?

How do I get it to print the number of times the string appears?

Habitual · 07-02-2015, 11:25 AM

grep -c does count the 'hits',so I start with that...
Try this:

Code:

#!/bin/bash
HITCOUNT=$(wget -q -O- http://www.centennialcollege.ca/programs-courses/centres-institutes/applied-research-and-innovation/for-students/job-postings/ | grep -c "Game Developer")
if [[ "$HITCOUNT" = 0 ]]  ; then echo "No Hits Found..." ; else echo Found "$HITCOUNT" hit\(s\) ; fi

Nexusfactor · 07-02-2015, 12:03 PM

Thanks, I like this approach much better!

Habitual · 07-02-2015, 12:53 PM

You are very welcome.