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Old 01-21-2006, 01:07 AM   #1
noir911
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Registered: Apr 2004
Posts: 682

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bash script problem


I have got a script which is not doing what it's
supposed to do.

In short, the script should grep the output of a
program, awk for one column & send an email to me if
anything from that column matches my criteria.

Code:
#!/bin/bash

BINARY="/usr/sbin/binary"
MAIL="/bin/mail"
RECPT="me@yahoo.co.uk"

SUB1="Number does match for `hostname`"
SUB2="Number doesn't match for `hostname`"

ERROR_VALUE="Please try again later"

# grep for specific column
PROG1="`$BINARY -l | grep -n 1 | awk {'print $7'}`"

# mail me to let me know that it is not working
PROG_ERR="`$BINARY -l | $MAIL -s "$SUB2" $RECPT`"

# mail me to let me know that it is working
PROG_OK="`$BINARY -l | $MAIL -s "$SUB1" $RECPT`"

# the total outout
PROG3="`$BINARY -l`"

# conditions
	if [ "$PROG1" = "0.00" ] || [ "$PROG1" -gt "1000" ]
|| [ "$PROG" = "1000" ]; then
	echo $PROG_ERR
	elif [ "$PROG3" == "$ERROR_VALUE" ]; then
	echo $PROG_ERR
	else
	echo $PROG_OK
fi
The program should scan all 3 or 4 lines in the column and grep for 0.00 or 1000 if there is any.

Any kind of help would be appreciated.
 
Old 01-21-2006, 06:02 PM   #2
bulliver
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Registered: Nov 2002
Location: Edmonton AB, Canada
Distribution: Gentoo x86_64; Gentoo PPC; FreeBSD; OS X 10.9.4
Posts: 3,760
Blog Entries: 4

Rep: Reputation: 78
Quote:
[ "$PROG" = "1000" ]
You have no $PROG variable in your script...

Also:
Code:
`$BINARY -l | grep -n 1 | awk {'print $7'}`
Here you are grepping for "1". This will match "1000" but not "0.00"

Last edited by bulliver; 01-21-2006 at 06:08 PM.
 
  


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