bash script, for all files in folder do ............

Simon_6162 · 07-18-2007, 01:22 PM

Hi I have a large number of files in a folder four example names are below.

This is a really long file name for a test 001.csv
This is a really long file name for a test 002.csv
This is a really long file name for a test 003.csv
This is a really long file name for a test 004.csv

I wanted to copy all the files in the current folder via ftp and rename them all to just the 001.csv 002.csv etc however if I do for files in `ls` the files names are split on the spaces in the names so $ file reads
this
is
a
really etc.

The solution I found was to do a string replace on the ls first using sed, which works, and then switch it back in the for loop but I'm just curious if there is a better solution to this.

This is the code I have:

Code:

#!/bin/bash

#copy files to the remote pc
for file in `ls *.csv | sed 's/ /~/g' `
do
	file1=`echo $file | sed 's/~/ /g'`
	file2=`echo $file1 | cut -c 44-`
	echo "copying file $file2"
	curl -T "$file1" -u uname:passwd ftp://192.168.5.230/"$file2"
done

so is it possible to not use sed ?

rose_bud4201 · 07-18-2007, 01:37 PM

An easier way is to override the IFS variable - it's what tells bash how to separate values, and it default to containing the space character, and -then- newlines.

See here for more info

Just be sure to back it up, first --

Code:

tempvar=$IFS
IFS="
"

...stuff...

IFS=$tempvar
exit

Simon_6162 · 07-18-2007, 02:40 PM

Thanks for your help that was what I was after. I obviously didn't look hard enough.

Simon