Bash loop using output of grep not working as needed
 

People

In a bash script I am writing I have a for loop that uses the output from a grep command to provide the data for the loop ie.

Problem is that the output of this is:

What I would like is for the CGI_DIR variable to have the complete line so the output becomes:

I will then use a nested loop to deal with each section of the variable.

I have tried putting the grep command in " " eg.

but then the output becomes:

This is a single line complete with a line break in the middle.

All documentation I have read says that grep outputs whole lines that match the criteria but I think bash then sees the spaces and chops it up.

Any thoughts on how to stop bash chopping up the grep output so I can deal with the whole line on each iteration?

3d

I believe the OP of this thread here - http://www.linuxquestions.org/questi...-good.-613980/ - is asking the same question.
Setting the IFS as chrism01 has suggested there, should suffice.

I would opt for

h/w

Cheers for the heads up. I did all sorts of searches before posting but who would have guessed what the thread was about by the title :(

Anyways I tried the suggestion of the IFS and got the same output as if I had used the " " around the grep command.

I then looked at the suggestion of using the read command and the following looks like it might do what I am after:

Note I am using the newer $( ) instead of the back quotes here but I had to put the echo/gawk command pipe in quotes as the comparison gave errors on some of the other lines in the input file.

Again thanks for the tip.

3d

colucix

Snap (almost) :)

Cheers
3d

use awk
depending on what you want to do after you get those lines

ghostdog74

Cheers for the response. I have the script working with the read command but I will keep the awk syntax in mind for future.

Cheers
3d

it can be simplified then, no need to call gawk for every line