LinuxQuestions.org - [SOLVED] BASH: if Variable -eq String not working

- Programming (https://www.linuxquestions.org/questions/programming-9/)

- - BASH: if Variable -eq String not working (https://www.linuxquestions.org/questions/programming-9/bash-if-variable-eq-string-not-working-784444/)

BASH: if Variable -eq String not working

Here is the code in question

Code:

# Determine which release of Debian is

# being used.

CODENAME=`lsb_release -c`



# Backup /etc/apt/sources.list

mv /etc/apt/sources.list /etc/apt/sources.list.bak



# Install the correct /etc/apt/sources.list

# file.

LENNY='Codename:      lenny'



if [ "$CODENAME" -eq "$LENNY" ] ; then

        cp $SRCDIR/files/aptsources/lenny /etc/apt/sources.list

fi

How ever when I run this script I get the following error

Quote:

./test.sh: line 57: [: too many arguments

Line 57 is the line that reads if [ "$CODENAME" -eq "$LENNY" ] ; then

I just don't get it, I have racked my brain trying to figure out every combination of how I should write this if statement and I can't get it to work. What am I doing wrong and why is it wrong?

Thanks

In the context in which you are using this code, the -eq operator is expecting integers. Just use an = sign instead.

DOH! It is always something simple. Thanks for pointing that out. Sometimes you just don't see the simplest errors and need a 2nd set of eyes.