Bash How to delete only one line from a file
 

Hi, i have a big problem.

I would like to delete a single line from a file that contains many lines passing through the same values ​​as the two parameters. Again, I would like to delete a single line and not all those that contain parameters. How can I make bash?

So you want a script that takes two parameters, and deletes the lines from a file that do not contain both of the strings that were passed as parameters?

No, I want to delete one line among all those who have those parameters.

For Example

1 parameter: Queen 2 parameter: News of the World

Queen News of the World
Beatles Revolver
Queen News of the World
....
...
I want to delete only the first Queen News of the World but not the last

I have try with awk, sed grep but nothing...Help Me...

So delete the first line that has both strings?

Here is an awk solution:

Thanks a lot.
One last thing. I saw that it is case sensitive.
Is there a way to get it case insensitive?

Yes, exactly.

In GNU awk you can set the internal variable IGNORECASE to a non-zero value (that is true). Example:
More details in the GNU awk manual: http://www.gnu.org/software/gawk/man...02dsensitivity

Hi,

if I understood correctly then there can be also an arbitrary amount of characters between the patterns and the order of the patterns does not matter, right? So these first lines would also be deleted if we use the parameters from your previous post:
Here is how you can do it with sed:

Yes, your script adds the ability to vary the order, but deletes all entries and not just one.

I think adding ;q inside the block will stop processing the file after changing the first occurrence.
{x;/^$/d;q}

Actually it exchanges the occurrences (each of them is replaced by the previous one). Example:

Doesn't this stop processing the rest of the file?

yes, it works. Ubuntu no problem, but on the Mac of my friend has a problem. But it's ok