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Old 05-05-2003, 05:43 AM   #1
davee
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bash - comparing a variable to several values


I've written a script which I want to check for valid input:

dom_option="";
while [ "$dom_option" != [s,r,q,c] ]; do
echo "Choose (s)tart, (r)estart, (q)uit server or (c)ancel."
read dom_option
done

What should I put where I've presently got s,r,q,c so it only accepts one of these values before exiting the loop? Do I have to put four 'or' statements in my comparison?

I know I've read the syntax somewhere, but can't find it...

Dave
 
Old 05-05-2003, 06:35 AM   #2
unSpawn
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If you only want to validate char dom_option you could present it as a case statement:
case "${dom_option}" in
s|r|q|c) continue;;
*) echo "Not a valid option"; exit 1;;
esac

...or you could use a "select" statement to only allow one option of s q r or c:
select action in exit s q r c; do
case "${action}" in
exit) echo "Exiting."; exit 0;;
*) echo "You selected \"${action}\""; break;;
esac
done

Other ways would be to use Bash' getopt or expr. Here's expr:
expr index "${dom_action}" "sqrc" >/dev/null
case "$?" in 1) echo "Not a valid option"; exit 1;; esac

Last edited by unSpawn; 05-05-2003 at 06:41 AM.
 
Old 05-05-2003, 06:52 AM   #3
Hko
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One way to do that:
(This also accepts uppercase answers.)
Code:
#!/bin/sh

while test -z "$dom_option" ; do
    echo "Choose (s)tart, (r)estart, (q)uit server or (c)ancel."
    read dom_option
    case "$dom_option" in
	s|S|r|R|q|Q|c|C) ;;
	*) dom_option="" ;;
    esac
done
echo "OK"
[edit]
Oops, was already answered by unSpawn while I was typing (too slow).
[/edit]

Last edited by Hko; 05-05-2003 at 03:54 PM.
 
Old 05-05-2003, 07:26 AM   #4
davee
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Registered: Oct 2002
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Thanks, folks, that's been a great help (as always!). Another script ready for users to break...

Does anyone think it's worth having a scripting forum, distinct from a programming forum?

Dave!

Last edited by davee; 05-05-2003 at 08:51 AM.
 
  


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