Bash child process in foreground while parent dies

kborgnis · 11-07-2007, 05:06 PM

Hello,

I'm writing a script that is meant to be run on a mounted CD. At the end of the script, I want to run another script which will be located on the local disk.

This secondary script will perform a few tasks in addition to ejecting the aforementioned CD, but will require user input. The problem I can't figure out is after the first script exits, control of the shell is given up and the second script fails because it is unable to read from STDIN.

How can I transfer control of the terminal to the second script?

Thanks,
kb

/media/cdrom/script-on-cd.sh

Code:

#!/bin/bash

echo "I'm on a CD"

/tmp/script-on-disk.sh &

/tmp/script-on-disk.sh

Code:

#!/bin/bash

echo "I'm on the local disk!"
sleep 10

eject

echo "Ejected!"
echo "More food please. Press enter when you're ready"
read CONTINUE

echo "Thanks!"

kborgnis · 11-07-2007, 05:39 PM

I feel like an idiot.

exec did just what I wanted. :-P

/media/cdrom/script-on-cd.sh

Code:

#!/bin/bash

echo "I'm on a CD"

exec /tmp/script-on-disk.sh

ta0kira · 11-08-2007, 12:10 PM

You really don't even need exec in this case. Just forego the &. Or you could just use a symlink. Or you could replace exec in your solution with ".".
ta0kira

kborgnis · 11-09-2007, 07:50 AM

Wouldn't the script located on the CD wait until the second script completed before it exited? Then wouldn't that prevent the CD from unmounting and ejecting?