[SOLVED] bash calling recursively a script

patolfo · 03-24-2010, 09:34 AM

Hi guys, i got this issue
I have a script which can get one argument, or many. If only one argument then, it call itself with the default behavior, however i can not find the way to call the script within its own body and passing some arguments to it:

This is the body of the decision tree:

Code:

if [ -z "$1" ]
	then 
        echo "Usage: $0 arg_name functions_to_run"
        exit
	else
		if [ $# -le 1 ] 
			then
				echo "0_o Not enough arguments, this function will run at default: $1 func1 func2 func3"
				$* $1 func1 func2 func3
				exit
			else
				if [ $# -ge 2 ]
							then
								FOO=("$@")
								for (( i=1; i<=$# -1; i++ ))
									do
										flujo $1 ${FOO[$i]} &
									done
							else
								echo "o_0 I am a ghost 0_o"	
				fi
		fi
fi

I tried with ./$0, but did not work

catkin · 03-24-2010, 09:49 AM

There is no dependable way for a script to find its own file as explained here.

One workaround would be to use a function and call it recursively.

grail · 03-24-2010, 09:11 PM

I am not real sure I understand the question??

Firstly is 'flujo' a program / command on your machine??

Secondly, please explain this part further:

Quote:

i can not find the way to call the script within its own body

If catkin's response about using recursive nature is what you are after then you would need to do
one of two things (assuming I am getting any of this):

1. Write a wrapper script to call this one and then recursively call yours
2. Wrap the actions in your script into a function and call it recursively from within your script.

patolfo · 03-25-2010, 10:05 AM

yep flujo is a function, which is called several times, with different arguments taken from the input when the script is called

What i was thinking is to made a default behavior, like if you have only one argument, to recall the script with three arguments added besides the first one.

let us say:

Code:

%name_of_script hola
if $# greater that one
then run script as normal
else call script with $1 new_arg1 new_arg2...

I was thinking lazy i know, right now i did an if fork to call the function internally with the arguments for the default operation, considering $#. How ever the doubt assaulted me, recursion for scripts is not possible then, i know the functions can be made recursively though.

catkin · 03-25-2010, 10:49 AM

No need for the script to call itself again, simply adjust the arguments in this instance (but this is almost certainly not the best way of achieving whatever it is you want to achieve)

Code:

default_arg2=<something>
default_arg3=<something>
[[ $# -eq 1 ]] && set "$1" "$default_arg2" "$default_arg3"
<parse arguments>
<other stuff>

patolfo · 03-25-2010, 04:43 PM

your code look interesting, care of explain it?

If i get it right, you actually add the arguments to the $@, array that allocates the input arguments given to the script, when called ...

catkin · 03-25-2010, 11:59 PM

Quote:

Originally Posted by patolfo

your code look interesting, care of explain it?

If i get it right, you actually add the arguments to the $@, array that allocates the input arguments given to the script, when called ...

Exactly. You can test it

Code:

for arg in "$@"
do
    echo "'$arg'"
done

The purpose of the double and single quotes is to make any leading or trailing whitespace visible.

patolfo · 03-29-2010, 11:25 AM

Quote:

Originally Posted by catkin

Exactly. You can test it

Code:

for arg in "$@"
do
    echo "'$arg'"
done

The purpose of the double and single quotes is to make any leading or trailing whitespace visible.

Yes it is what i wanted

Thanks a bunch!

catkin · 03-29-2010, 11:38 AM

Quote:

Originally Posted by patolfo

Yes it is what i wanted

Thanks a bunch!

You're welcome

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