Bash Awk Variable problem
 

Dear all,
I want to find a PID of a certain program.
I have same program running with different parameters and want to find the PID based on the parameter

./program conf1.conf
./program conf2.conf
./program conf3.conf

So I Used:

#!/usr/bash
...
$param_name = $1
pid=$(ps x | grep ./program | grep $param_name | gawk "{ print $1 }")
...

My problem is that when I use this command in my script file,
$1 is replaced by the script's frist parameter

I mean

./myscript conf1
causes

pid=$(ps x | grep ./program | grep conf1 | gawk "{ print conf1 }")

and so the $pid variable remains empty.

Any ideas?

You are not escaping the $ or using single quotes to prevent substitution, so of course the parameter is substituted. You want to pass the string '$1' to gawk, not the value of $1.

Either of these should work:

Just an idea: why not use pgrep?

You'll probably find it on your system even if it's not FreeBSD.

I second pgrep

Thanks to macemoneta
but unfortunately both ways did nothing :(

I'm trying pgrep and pkill

Thanks to taylor_venable :)

Thanks Pkill was great.