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Old 08-21-2008, 01:52 PM   #1
schneidz
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bash - awk, sed, grep, ... advice


[aix]
hi, i have a file like:
Code:
=====
hello
world
file-id:200
aller
spica
=====
l33t
file-id:500
hax0rz
=====
chun-li
akuma
gouki
file-id:42
ken
ryu
sakura
morrigan
dark-sakura
i'd like to print the lines in between the '====='s.
for example: for file-id:500, i want the output
Code:
=====
l33t
file-id:500
hax0rz
=====
there are a variable amount of lines between '====='s.

is there a simple way of doing it ?
 
Old 08-21-2008, 02:35 PM   #2
matthewg42
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How big is the input file? Will it easily fit in memory?
 
Old 08-21-2008, 03:04 PM   #3
schneidz
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not terribly big:
Code:
 wc -l file.in
    5321
 wc -c file.in
  192741
 
Old 08-21-2008, 03:41 PM   #4
ilikejam
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Code:
#!/bin/bash
awk 'BEGIN {RS="\n=====\n"} /'$1'/ {print}'
Call the script with file-id:xyz as the argument.

Dave

Last edited by ilikejam; 08-21-2008 at 03:42 PM.
 
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Old 08-21-2008, 05:12 PM   #5
schneidz
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thanks, this doesnt quite work for me:
Code:
schneidz@lq> cat ilikejam.lst | ilikejam.ksh 500
file-id:500
any other suggestions. i'll man up on awk so i can figure out how to print everything between record separators, not just the line that matches.

regards,
 
Old 08-21-2008, 11:15 PM   #6
allez
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Here is a quick and dirty solution (probably someone will find a better one), but it seems to work:
Code:
allez@home:~/tmp> cat file.in
=====
hello
world
file-id:200
aller
spica
=====
l33t
file-id:500
hax0rz
=====
chun-li
akuma
gouki
file-id:42
ken
ryu
sakura
morrigan
dark-sakura

allez@home:~/tmp> cat search.sh
#!/bin/sh

if [ "$#" != "2" ];
then
  echo "Usage: $0 <file> <string_to_search>"
  exit 1
fi

search_file="$1"
search_string="$2"
cat "$1" | tr "\n" "%" | sed 's/\=\%/\n/g' | grep "$2" | tr "%" "\n" | grep -v "^=*$"

allez@home:~/tmp> ./search.sh file.in "file-id:500"
l33t
file-id:500
hax0rz

allez@home:~/tmp> ./search.sh file.in "ryu"
chun-li
akuma
gouki
file-id:42
ken
ryu
sakura
morrigan
dark-sakura
 
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Old 08-22-2008, 12:03 AM   #7
ghostdog74
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Code:
awk 'BEGIN {RS="===="} /file-id:500/' file
 
1 members found this post helpful.
Old 08-22-2008, 09:02 AM   #8
schneidz
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Quote:
Originally Posted by ghostdog74 View Post
Code:
awk 'BEGIN {RS="===="} /file-id:500/' file
i tested ghostdog's and it works quite nicely, thanks.

my only peculiarity i have is:
Code:
schneidz@lq> h=42
schneidz@lq> echo $h
42
schneidz@lq> awk -v h=$h 'BEGIN {RS="===="} /h/' ilikejam.lst

hello
world
file-id:200
aller
spica


l33t
file-id:500
hax0rz


chun-li
akuma
gouki
file-id:42
ken
ryu
sakura
morrigan
dark-sakura
still fine-tuning. i'll re-post with my progress.
regards,
 
Old 08-22-2008, 10:04 AM   #9
schneidz
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although slightly more complex a tweaked allez example allows for variable substitution:
Code:
schneidz@lq> cat allez.ksh
#!/bin/sh

if [ "$#" != "2" ];
then
  echo "Usage: $0 <file> <string_to_search>"
  exit 1
fi

search_file="$1"
search_string="$2"
cat "$1" | tr "\n" "%" | tr "=%" "\n" | grep "$2" | tr "%" "\n" | grep -v "^=*$"


schneidz@lq> allez.ksh ilikejam.lst $h
chun-li
akuma
gouki
file-id:42
ken
ryu
sakura
morrigan
dark-sakura
thanks for everyone's help.
__________
edit:
and then maybe there's this:
Code:
grep -p=====  $h ilikejam.lst
chun-li
akuma
gouki
file-id:42
ken
ryu
sakura
morrigan
dark-sakura

Last edited by schneidz; 08-22-2008 at 11:17 AM. Reason: my stupidity
 
Old 08-22-2008, 11:33 AM   #10
ghostdog74
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Quote:
Originally Posted by schneidz View Post
42
schneidz@lq> awk -v h=$h 'BEGIN {RS="===="} /h/' ilikejam.lst
/h/ means match a "h". It does not mean match the value of the variable h. In order to do that, change /h/ to
Code:
$0 ~ h
 
Old 08-22-2008, 12:04 PM   #11
sundialsvcs
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When faced with a problem like this, I immediately consider that awk was designed specifically to handle moderately-complex file processing jobs like this one; and that the entire perl programming language was, in one sense, "built on top of 'awk.'" Therefore, I have two heavyweight programming tools at my disposal.

It's important to consider solutions that are descriptive of the problem being solved: not merely "something that 'works now.'" It needs to work well in the general case.

The Perl community has a saying: "TMTOWTDI" = "There's More Than One Way To Do It." And that's very true.

Sometimes a good solution to a problem can be discovered by re-stating it, thusly:
Quote:
"Print all of the lines in the source-file that are not equal to '====='."
If that is a valid definition of your problem, then grep could be used to "print all lines in this file which do not match the following regular-expression ('string pattern')."
Quote:
grep -v /^=====$/ filename
(The regular-expression uses the "^" and "$" anchors, which mark "start of line" and "end of line" respectively, to match lines that consist of five equals-signs. The "-v" command-line option inverts the test to print all non-matching lines.)

"TMTOWTDI!" "TMTOWTDI!" More than one 'solution' will 'work!' The one that you're looking for is the one that is easiest to implement and that solves the problem most-completely in the general case.
 
Old 08-25-2008, 01:47 AM   #12
chakka.lokesh
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I have seen this thread on the first day of the posting itself. I thought solution exists using sed itself. ofcourse I am learning awk. I have to improve my skills in writing awk program. using awk may be better too.

but I have a solution using sed.

Code:
sed -n '/500/ {;H;b one;};/=====/ {;h;b;};H;b;:one;n;/=====/ {;g;p;b;};H;b one;' <inputfile>

I was not able to give time to this question. Today I did it. hope it will be useful to OP and others ofcourse .

first line will be ===== .
To optimize the code, I allowed it to be there in the output.....
 
Old 08-25-2008, 08:00 AM   #13
matthewg42
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Funky Perl:
Code:
perl -e '$/="====="; map { s/^$//; printf "=====%s\n", $_ if (/file-id:500/); } <>' in_file
 
Old 08-25-2008, 09:30 AM   #14
makyo
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Hi.

Windowing requirements seem to occur frequently. I often use cgrep for such tasks:
Code:
#!/bin/bash -

# @(#) s1       Demonstrate windowing feature of cgrep.
# http://www.bell-labs.com/project/wwexptools/cgrep/

echo
echo "(Versions displayed with local utility \"version\")"
version >/dev/null 2>&1 && version "=o" $(_eat $0 $1) cgrep
set -o nounset
echo

FILE=data1
pattern=${1-"file-id:500"}

echo " Results:"
cgrep -D -+w '^===' "$pattern" $FILE

exit 0
Producing:
Code:
$ ./s1

(Versions displayed with local utility "version")
Linux 2.6.11-x1
GNU bash 2.05b.0
cgrep (local) - no version provided for ~/executable/cgrep.

 Results:
=====
l33t
file-id:500
hax0rz
=====
See the URL for a source download. The cgrep utility as many more features than this, and, since you have the source, you can place it on other systems you use. On the one I used here, I have it installed in a private directory ... cheers, makyo
 
  


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