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rejeep 11-27-2007 12:40 PM
Bash array to function
 
Hi!

How can I manipulate an array in BASH?

For example. After the call of function a I want the first element in the array to have been removed. So the output after the call should be b c.
Code:
#!/bin/bash

function a()
{
    unset $1[0]
}

array=( "a" "b" "c" )
echo "${array[@]}" // Output is "a b c"
a "${array[@]}"
echo "${array[@]}" // Output is "a b c", but should be "b c"
Thanks!

slakmagik 11-27-2007 12:55 PM
What exactly are you trying to do? $1 is not an array variable. You would delete an array index with 'unset array[0]'. And then the function doesn't get you much, as it's a one token reference to a one token command.

rejeep 11-27-2007 12:59 PM
Quote:
Originally Posted by digiot (Post 2972397)
What exactly are you trying to do?
I'm trying to manipulate an array in a function where the array was given as an argument to the function.

In the example above I'm trying to remove the first element from the array named array.

radoulov 11-27-2007 01:40 PM
Quote:
Originally Posted by rejeep (Post 2972402)
I'm trying to manipulate an array in a function where the array was given as an argument to the function.

In the example above I'm trying to remove the first element from the array named array.
Code:
bash 3.2.25(1)$ array=( "a" "b" "c" )
bash 3.2.25(1)$ echo "${array[@]}"
a b c
bash 3.2.25(1)$ a(){ unset "$1"[0];}
bash 3.2.25(1)$ a array
bash 3.2.25(1)$ echo "${array[@]}"
b c

rejeep 11-27-2007 01:45 PM
Thanks! =)

radoulov 11-27-2007 02:05 PM
Quote:
Originally Posted by rejeep (Post 2972443)
Thanks! =)
Consider that after removing the first element,
the next time you run a array nothing will happen
(you'll have no more ${array[0]} element.


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