Bash arithmetic

Blackout_08 · 06-08-2006, 09:12 PM

I have this

echo $((00060108-1))
-bash: 00060108: value too great for base (error token is "00060108")

Im using bin/bash. I need to be able to do this statement. It only does it when the last digit is 8-9. Help please

perfect_circle · 06-08-2006, 10:04 PM

Yeah, this is because the number starts with 0.
In bash every number that starts with 0 is considered octal (having 8 as a base) and not decimal.

SO you cannot have a number starting with 0 and containing the digits 8 and 9 inside

perfect_circle · 06-08-2006, 10:37 PM

You may strip the leading zeros, like this for example:

Code:

skalkoto@darkstar:~$ number=000657999
skalkoto@darkstar:~$ without_zero=$(echo $number |sed 's/0*//')
skalkoto@darkstar:~$ echo "$without_zero"
657999
skalkoto@darkstar:~$

or use bc instead:

Code:

skalkoto@darkstar:~$ echo "0006999 -1" | bc
6998
skalkoto@darkstar:~$