awk printing from Nth field to last field

sebelk · 01-08-2010, 08:53 AM

Hi,

How can print the, let's say 5nd field to the last field of every record (let's say we have 10 fields)?

I mean: I cant avoid to have to do:

print '{$5 $6 $7 $8 $9 $10}'

Thanks in advance!

colucix · 01-08-2010, 09:11 AM

Awk has not a syntax to specify a fields interval (ghostdog74, correct me if I'm wrong) but you can manage it using a for loop:

Code:

for ( i = 5 ; i <= NF; i++ ) print $i

On the other hand, if it is a one-liner better to use cut in place of awk:

Code:

$ cut -d' ' -f5- file

ghostdog74 · 01-08-2010, 09:39 AM

you can do it like colucix showed or you can set $1=$2=$3=$4="" (and if you don't mind an extra space , which you can gsub() away).