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It's like a puzzle. Like for instance, the decimal equivalent of "a" is 97, like in the Ascii table. But the the total of all the letters in the word added up have to be between those numbers.
OK.... The sum of the ascii values for "abc" would be 303. Take 100 letters with an average value of 110 (n), and you get 11,000. Getting to 927,000 will take one heck of a word......
Please disambiguate what you mean by
Quote:
all the letters in the word added up
Also, the first number in the title is not the same as in the text.
It's like a puzzle. Like for instance, the decimal equivalent of "a" is 97, like in the Ascii table. But the the total of all the letters in the word added up have to be between those numbers.
Distribution: Solaris 11.4, Oracle Linux, Mint, Debian/WSL
Posts: 9,789
Rep:
As I wrote, I used brute force. That means instead of trying to find a solution using some sort of logical approach, I slightly modified the C code for it to try every word from an English dictionary.
I quickly found 277 out of 109582 words were passing the test.
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