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Old 12-26-2017, 07:15 AM   #1
pedropt
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Arrange numbers in sequence from a variable


This is probably a simple code , but i was looking in sort command and none of the switches work for this case .

for example :

Code:
#!/bin/bash
echo -n "Write a number not in order : "
read -r mynmb
varout=$(echo $mynmb | sort -n)

echo""
echo "You wrote : $mynmb  and was arranget in order by this : $varout"
basically i want to arrange :
example :

from : 283741 to 123478

This is probably simple , but i cant get into it directly from a variable .

Last edited by pedropt; 12-29-2017 at 03:11 AM.
 
Old 12-26-2017, 08:11 AM   #2
keefaz
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Probably the ugliest way
Code:
varout=$(echo -n $mynmb | fold -w1 | sort -n | tr -d "\n")

Last edited by keefaz; 12-26-2017 at 08:12 AM.
 
Old 12-26-2017, 08:18 AM   #3
michaelk
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Sort works on a data set or list not a single string.
Along the same line of thought... grep -o . separates the number before it gets piped to sort and recombined by tr.
Code:
$varout=$(echo $mynmb | grep -o . | sort | tr -d "\n")
Or perl
Code:
$varout=$(echo $mynmb | perl -F -lane 'print sort @F')
 
Old 12-26-2017, 09:01 AM   #4
pedropt
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Thanks guys , it works perfectly .

Let me just leave the correct code here finished for others to use :

Code:
#!/bin/bash
echo -n "Write a number not in order : "
read -r mynmb
varout=$(echo $mynmb | grep -o . | sort | tr -d "\n")

echo""
echo "You wrote : $mynmb  and was arranged in order by this : $varout"
 
Old 12-26-2017, 09:28 AM   #5
keefaz
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If the user doesn't know, I wonder what he/she will understand with:
"Write a number not in order"

I know I would be stuck at this point
 
  


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