ArithmeticException missing with Java?

pycoucou · 04-13-2004, 09:24 AM

Just to have your point of view...

I am performing a division so instead of testing the nullity of my denominator, I thought it was smarter (and faster) to catch an ArithmeticException and set the result of the division to zero if it would occur. Unfortunately, there's nothing thrown....

Do you know why?

PS: it's not important while I added a test but I would like to understand.

moeminhtun · 04-13-2004, 09:43 AM

If the denominator is 0, it will throw ArithmeticException.
Check your code again.
Or run the test program

public class Test {
public static void main(String[] args) {

int a = 1;
int b = 0;
int result = 0;

try {
result= a/b;
} catch (ArithmeticException e) {
System.out.println("ArithmeticException, set result to 0");
result = 0;
}

System.out.println(result);

}
}

pycoucou · 04-13-2004, 09:59 AM

Quote:

Originally posted by moeminhtun
Or run the test program

Alright... the test program gives me the exception. The error seems to occur for a and b double. Why? The result in this case is infinity. The program I used to run gave me NaN. Do you have an idea why there are such different behaviours?

moeminhtun · 04-13-2004, 11:36 AM

Then your program must be performing the floating point calculation.
In Java, only the Integer division by zero, including modulo(%) operation, results in an ArithmeticException. If floating point, it won't throw any exception and it will return a NaN.