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Just curious as to others' interpretations on this.
If it were to be considered streamlined that this operator is excluded... is it because the particular operator that would be required would take up just a little bit more resource?
Seems silly that it takes all three logical operators to form an exclusive-OR operation in C++ and then to call it streamlined (by some).
Keep in mind that ^ is bitwise and values need to be converted to bool in order for it to be a boolean operation. There's no boolean XOR (in the way && corresponds to &) as far as I know.
ta0kira
That works with true boolean values, but what about this?
Code:
#include <stdio.h>
int main()
{
int A = 1, B = 2;
if (A != B) printf("!=\n"); /* compares numerical values */
if ((bool) A !=(bool) B) printf("XOR 1\n"); /* same as below but no shorter */
if ((bool) A ^(bool) B) printf("XOR 2\n"); /* boolean XOR */
}
When comparing non-bool values, && and || automatically convert the two to perform a true boolean comparison so (bool) isn't needed. ^ has nothing comparable in that sense, which is especially a problem in C.
ta0kira
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