about -d, -s with $@ in Makefile

George2 · 04-26-2006, 02:47 AM

Hello everyone,

What are the meaning of -s, -d with $@ in Makefile? For example,

[ -d $@ ] || (other commands)

[ -s $@ ] || (other commands)

thanks in advance,
George

ioerror · 04-26-2006, 04:59 AM

These are shell commands. See man test.

George2 · 04-26-2006, 06:57 AM

Thanks ioerror,

Quote:

Originally Posted by ioerror

These are shell commands. See man test.

I got them! Previously, I thought they are make commands. :-)

What means $@? I can not find related descriptions in GNU make manual, even if it is used several times in it.

regards,
George

bigearsbilly · 04-26-2006, 07:20 AM

make doesn't have commands...

Code:

target:
        do something       # anything HERE is run with what's in $SHELL, e.g. /bin/sh

eg as above

/bin/sh -d blah.blah

ioerror · 04-26-2006, 07:29 AM

$@ expands to the current target.

George2 · 04-27-2006, 05:02 AM

Thanks ioerror,

Quote:

Originally Posted by ioerror

$@ expands to the current target.

It makes senses.

regards,
George

George2 · 04-27-2006, 05:04 AM

Thanks bigearsbilly,

Quote:

Originally Posted by bigearsbilly

make doesn't have commands...

Code:

target:
        do something       # anything HERE is run with what's in $SHELL, e.g. /bin/sh

eg as above

/bin/sh -d blah.blah

Do you mean the question I asked is dealing with shell commands and has nothing to do with make itself?

regards,
George